t-test for independent means:
n=8
t=-1.33
df= 8
C.V. = plus or minus 2.306
My question is how do you get 2.306 for the cv???
Why wouldnt the cv be 2.31?
If by C.V. you mean Coefficient of Variation, then CV shows the variation as a percentage of the mean and can be calculated as follows:
CV% = (SD/mean)100