a compound x has a solubility of 79g/100 g h20. when 24 g of x are added to 68 g of water the resulting mixture is homogeneous or heterogenous
I usually work this type by calculating how much water is required to dissolve 24 g. We know it takes 100 g H2O to dissolve 79 g of x so
100 * (24/79) = ?? is the amount of water required to dissolve 24 g. Then compare that number with the amount of water you have (68g). If you have enough water to dissolve the salt then you have a homogeneous solution. If you have less water than needed to dissolve the salt you will have a saturated solution and two phases which is a heterogeneous mixture.
To determine if the resulting mixture is homogeneous or heterogeneous, we need to compare the amount of solute (compound x) added to the amount of solvent (water).
In this case, 24 g of compound x is added to 68 g of water. To calculate the solubility, we need to compare the amount of solute dissolved in the solvent.
The given solubility of compound x is 79 g/100 g H2O, which means that 79 g of compound x can dissolve in 100 g of water.
To determine if all of the 24 g of compound x can dissolve in 68 g of water, we can establish a ratio by dividing the amount of compound x by the amount of water:
24 g compound x / 68 g water = (24/68)
To find out if this ratio (24/68) is greater than or equal to the solubility ratio (79/100), we can cross-multiply:
24 x 100 = 68 x 79
Simplifying this equation gives us:
2400 = 5372
Since 2400 is not equal to 5372, it means that the ratio (24/68) is smaller than the solubility ratio (79/100).
This suggests that not all of the 24 g of compound x can dissolve in 68 g of water. Therefore, the resulting mixture will be heterogeneous, as some solid compound x will remain undissolved in the water.