Saturday

August 23, 2014

August 23, 2014

Posted by **KIKI** on Tuesday, August 2, 2011 at 10:47am.

If it weren't for the "3" I know I could just "move" the exponent of 2 from sin^2 to in front of the ln,....but because of the 3 I can't do this....So what should I do?

Thank you very much for your help! Have a nice day :)

- Calculus -
**drwls**, Tuesday, August 2, 2011 at 11:09amLet u = sin^2x + 3

f(x) = ln[sin^2(x)+3]

= ln u(x)

df/dx = df/du*du/dx

= (1/u)*2sinx*cosx

= sin(2x)/[sin^2x+3]

- Calculus -
**KIKI**, Tuesday, August 2, 2011 at 3:55pmthank you! but how did you go from......(1/u)*2sinx*cosx....to......sin(2x)/[sin^2x+3].............? i was just confused by this..thanks

**Related Questions**

Calculus 12th grade (double check my work please) - 1.)Find dy/dx when y= Ln (...

calculus - Could someone check my reasoning? thanx Find the derivative of the ...

Calculus I - Find the derivative of f(x) = sin^2 (e^sin^2 x) I wonder if I'm ...

pre-calculus - I am having trouble with trigenometric identities I cannot figure...

trig integration - i'm having trouble evaluating the integral at pi/2 and 0. i ...

Calculus - Consider the function f(x)=sin(1/x) Find a sequence of x-values that ...

Calculus - f(x)=sin^(7)x The 7 is an exponent and the x is not. Find the ...

COLLEGE CALCULUS. HELP! - i dont know how to start this problem. i dont like cos...

Calculus - Consider the function f(x)=sin(1/x) Find a sequence of x-values that ...

Calculus - Consider the function f(x)=sin(1/x) Find a sequence of x-values that ...