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April 18, 2015

Posted by **Aria** on Tuesday, August 2, 2011 at 1:58am.

Find The LCM for

#1

2(R-7) and 14(R-7)

#2

(1+4r), (1-16r^2), and (1-4r)

It seems like #1 is already at the LCM

and #2 would be (1+4r)(1-4r)

Am I even vaguely correct?

Thanks for your help.

- Algebra -
**MathMate**, Tuesday, August 2, 2011 at 8:53amAs you probably know, if one number is a multiple of the other, the bigger number is the LCM of the two.

Post your exact answer to #1 to confirm if you wish.

For #2, you are more than vaguely correct, but you do not appear to have any justification of your response.

You can confirm your thoughts by dividing the LCM by each of the three values. If they all divide without remainder,*and*there is no common factor between the quotients, the answer is correct.

For example,

If 60 is the LCM of 5,6,15, then

60/5=12 has no remainder

60/6=10 has no remainder

60/15=5 has no remainder.

However,

5,10 and 12 have a common factor of 2, so 60 is*not*the LCM, but 60/2=30 is!

Feel free to post your justification of your answer along the lines above.

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