Posted by **Jen** on Monday, August 1, 2011 at 7:34pm.

find the center and radius of a circle given the equation in general form

x^2+y^2+4x-6y+2=0.

center: ?

radius: ?

- math -
**Ms. Sue**, Monday, August 1, 2011 at 7:44pm
Please use the same name for all of your posts.

By using different names, you're usurping names that are already used by other students.

- math -
**Jen**, Monday, August 1, 2011 at 7:46pm
I am not sure what you're talking about.

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**Ms. Sue**, Monday, August 1, 2011 at 7:51pm
Meghan, John, and Jen all have the same ip address, a computer in St. Louis, Missouri.

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**drwls**, Monday, August 1, 2011 at 8:30pm
Rewrite the equation in the form

(x + 2)^2 + (y - 3)^3 = 11

This shows that it is a circle centered at x = -2, y = 3.

See of you can guess the radius, from the constant term on the right.

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