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October 20, 2014

October 20, 2014

Posted by **Jen** on Monday, August 1, 2011 at 7:34pm.

x^2+y^2+4x-6y+2=0.

center: ?

radius: ?

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**Ms. Sue**, Monday, August 1, 2011 at 7:44pmPlease use the same name for all of your posts.

By using different names, you're usurping names that are already used by other students.

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**Jen**, Monday, August 1, 2011 at 7:46pmI am not sure what you're talking about.

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**Ms. Sue**, Monday, August 1, 2011 at 7:51pmMeghan, John, and Jen all have the same ip address, a computer in St. Louis, Missouri.

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**drwls**, Monday, August 1, 2011 at 8:30pmRewrite the equation in the form

(x + 2)^2 + (y - 3)^3 = 11

This shows that it is a circle centered at x = -2, y = 3.

See of you can guess the radius, from the constant term on the right.

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