Posted by **Meghan** on Monday, August 1, 2011 at 7:28pm.

Okay, I need to find the 101th term of the sequence 5,9,13,17,21...

Do I do this:

a1 + (n-1)d

SO...

5+(101-1)4

5+(100)4

105x4

420

Did I do this problem correctly?

- Math -
**MathMate**, Tuesday, August 2, 2011 at 9:08am
Almost!

First, check your formula against values:

a1+(n-1)d

where a1=5, d=4, and n=term number

For the first term, n=1

5+(1-1)*4=5 correct

For the third term:

5+(3-1)*4=5+2*4=13 correct.

So there is a good chance the formula.

Now do the calculations for the 101th term:

5+(101-1)*4

=5+100*4

Remembering that in all calculations, the priority of operations is in the order:

()

* or ÷

+ or -

So we need to multiply before add, or

5+100*4

=5 + (100*4)

=5 + 400

= 405

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