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April 1, 2015

April 1, 2015

Posted by **brit** on Monday, August 1, 2011 at 1:35pm.

Numerical Answers Expected!

- math -
**PsyDAG**, Monday, August 1, 2011 at 3:12pmJ = T + 10

J-3 = 2(T-3)

Substitute T+10 for J in second equation and solve for T. Insert that value into the first equation and solve for J. Check by inserting both values into the second equation.

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