Which one of the following will have the greatest number of moles of potassium ion: 10.0 mL of .10 M potassium hydroxide, 30.0 mL of 0.15 M potassium carbonate, or 25.0 mL of 0.080 M potassium phosphate

moles K3PO4 = M x L = 0.080 x 0.0250L = 0.002. Since there are three K^+ in 1 molecule of K3PO4 there will be 0.002*3 = 0.006 moles K^+ in that sample. The others are done the same way.

To determine which solution will have the greatest number of moles of potassium ion, we need to calculate the number of moles for each solution. The formula to calculate the number of moles is:

number of moles = concentration × volume (in liters)

Let's calculate the number of moles for each solution:

For the first solution, 10.0 mL of 0.10 M potassium hydroxide:
Number of moles = 0.10 mol/L × 0.010 L = 0.001 moles of potassium ion

For the second solution, 30.0 mL of 0.15 M potassium carbonate:
Number of moles = 0.15 mol/L × 0.030 L = 0.0045 moles of potassium ion

For the third solution, 25.0 mL of 0.080 M potassium phosphate:
Number of moles = 0.080 mol/L × 0.025 L = 0.002 moles of potassium ion

Now, we can compare the number of moles for each solution. The solution with the greatest number of moles of potassium ion is the second solution, which contains 0.0045 moles of potassium ion.

So, 30.0 mL of 0.15 M potassium carbonate will have the greatest number of moles of potassium ion.