Posted by Jennifer on Sunday, July 31, 2011 at 9:56pm.
Let
S=number of bags of sticky bears, then
400-S=number of bags of chocolate bombs.
From total cost = $500, we get
1.5S+1.0(400-S)=500
Solve for S
0.5S = 500-400
S=200
Quick way:
each bag of sticky bears costs 1.50
each bag of chocolate costs 1.00
Average cost = $500/400=1.25
which is smack in between 1.00 and 1.50.
So equal number of bags of each, namely 200.
Related Questions
math - april sells specialty teddy bears at various summer festivals. her profit...
algebra - Bear population. To estimate the size Use a proportion to solve of the...
English - Yeot is a traditional Korean sweet like taffy. It is made from sweet ...
Science - Are black bears and white bears the same species? why or why not?
Physics - At a county fair, a boy and two friends bring their teddy bears on the...
Physics - At a county fair, a boy and two friends bring their teddy bears on the...
Math Word Problem - In an NFL football game, the Bears scored a total of 41 ...
Help On Math - A movie theater has fixed costs of $5,500 per day and variable ...
Kinder math - Cover the teddy bears in the top row with different color teddy ...
7th Grade Lit - What is the complement of: a) "The snake looks hungry."...
For Further Reading