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October 25, 2014

October 25, 2014

Posted by **Lacy** on Sunday, July 31, 2011 at 8:51pm.

- algebra (college) -
**Henry**, Monday, August 1, 2011 at 4:34pmN = (6*10^-5)x^3 + (600*10^-5)x^2 -0.1x+1.4.

N = (6*10^-5)(1.75)^3 + (600^10^-5)(1.75)^2 - 0.1x + 1.4,

N = (6*10^-5)5.36 + (600*10^-5)3.06

- 0.175 + 1.4,

N = 35.22*10^-5 + 1836*10^-5 - 0.175 + 1.4,

N = 1871.2 *10^-5 + 1.23,

N = 0.018712 + 1.23 = 1.24 Million.

Part 2: Use same procedure except X = 3.

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