Posted by raven on Sunday, July 31, 2011 at 5:18pm.
5/4(cos225 + isin225) =
1.25(-0.7071 - i0.7071) =
-0.8839 - i0.8839 =
tanA = -0.8839 / -0.8839 = 1,
A = 45 deg. = 45 + 180 = 225 deg, Q3.
Since the X and Y components are neg,
our resultant vector is in Q3.
r = -0.8839 / cos45 = -1.25 @ 225 deg,
Q3.
Related Questions
Precalc - Represent the complex number graphically and find the standard form of...
Calculus - Determine the polar form of the complex number 3 - 2i. Express the ...
Calculus - Given Z = 2(cos 148° + isin 148°) and W = 5(cos 11° + ...
precal 2 - find the cube roots of the complex numbers -4square root 2(1-i) and ...
trigonometry - 1)Solve and write in standard form: 4x^2-4x+21=0 2)Find the ...
precal - identify the standard form of the complex number: 10(cos259+isin259)
precalc - Suppose that z1=6-8i. Find: A. The Trig Form of the complex number z1...
pre-calculus - Graph each complex number. Then express it in rectangular form. 2...
Calculus II - What is sin(i) -- (sin of the imaginary number, i) What is cos(i...
complex numbers! - -2-2i in polar form = 2.8 cis 2.35?? -3+4i polar form = 5 cis...
For Further Reading