Posted by eve on Sunday, July 31, 2011 at 7:32am.
let's look at t hrs after the above condition
let the distance between them be D miles
then
D^2 = (40t+8)^2 + (15+60t)^2
2D dD/dt = 2(40t+8)(40) + 2(15+60t)(60)
dD/dt = [ 40(40t+8) + 60(15+60t) ]/D
when t = 0 , the above condition,
D = √8^2+15^2) = 17
and
dD/dt = [ 40(8) + 60(15) ]/17 = 71.76
At that moment they are separating at 71.8 mph
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