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Posted by **Melanie** on Saturday, July 30, 2011 at 7:38pm.

Find the half-life of Cesium-137 (Round to the nearest year)

How much Cesium-137 is left in the sample after 60 years? Round to the nearest tenth of a gram.

- algebra -
**drwls**, Sunday, July 31, 2011 at 10:32amIf T is the half life,

(1/2)^(t/T) = 0.16/0.20 = 0.80

where t = 10 yr

(t/T) = 0.3219

T = 31 yr

After 60 yr, the fraction left is

(0.5)^(60/31) = 0.261

Amount left = 200*0.261 = 52.3 g

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