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December 21, 2014

Homework Help: chemistry

Posted by % ionization on Saturday, July 30, 2011 at 7:13pm.

What is the percent ionization of 0.025 M chlorous acid, HClO2 solution?

Ka HClO2 = 1.1*10^(-2)

Answer: 48%

What I did:

HClO2(aq) + H2O(l) -><-
ClO2(aq) + H3O(aq)

initial-change-end table results:

x^(2)/(.025-x)=1.1*10^(-2) x=1.6*10^(-2)

% ionization = (1.1*10^(-2))/(1.6*10^(-2))*100 = 69%

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