Wednesday
April 16, 2014

Homework Help: chemistry

Posted by pH levels on Saturday, July 30, 2011 at 7:02pm.

What is the pH of an aqueous solution of 0.10 M NaHC(3)H(2)O(4)?

Answer: 10.9

What I did:

NaHC(3)H(2)O(4) + H(2)O--><--
Na + H(2)C(3)H(3)O(4) + OH

H(2)C(3)H(3)O(4) is Malonic acid with a Ka value of 1.5*10^(-3)

initial-change-equilibrium (i.c.e) table results: (x^2)/(0.10-x)

x= 8.16*10^(-7)

[OH] = x
pOH = -log(x)
pH = 14-pOH
pH = 7.91

not sure what I did wrong.

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