Posted by Jeff on Saturday, July 30, 2011 at 11:08am.
let each side of the cut-outs be x cm
So the base is 60-2x by 40-2x and the height is x
Volume = x(60-2x)(40-2x)
= 4x^3 - 200x^2 + 2400x
d(volume)/dx = 12x^2 - 400x + 2400
= 0 for a max of volume
3x^2 - 100x + 600 = 0 ----- I divided by 4
x = (100 ± √(2800)/6
= 25.5 or 7.85
but clearly 0 < x < 20 or else the sides make no sense.
so the cut-outs should be 7.85 by 7.85 cm
Plug 7.85 into my volume expression to get the max volume
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I'm confused. Thanks in advance for any help.
Tony has a rectangular piece of cardboard which is 60 cm by 40 cm. By cutting squares from each corner of the cardboard and turning up the sides, can he form an open-topped box which will hold (a) 6656 cubic centimeter? (b) 9000 cubic centimeters? (c) what is the maximum amount of space he can obtain?
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