Algebra
posted by
Meghan
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Solve the logarithmic equation.
log2(4x)log2(x+3)=1

Algebra 
Reiny
log_{2}(4x  log_{2}(x+3) = 1
log_{2}(4x/(x+3)) = 1
4x/(x+3) = 2^1 = 2
4x = 2x+6
2x = 6
x = 3

Algebra 
Meghan
Thanks for your help!! I knew how to start, just wasn't sure the steps to go!