Posted by **Meghan** on Friday, July 29, 2011 at 7:32pm.

Solve the logarithmic equation.

log2(4x)-log2(x+3)=1

- Algebra -
**Reiny**, Friday, July 29, 2011 at 7:36pm
log_{2}(4x - log_{2}(x+3) = 1

log_{2}(4x/(x+3)) = 1

4x/(x+3) = 2^1 = 2

4x = 2x+6

2x = 6

x = 3

- Algebra -
**Meghan**, Friday, July 29, 2011 at 7:40pm
Thanks for your help!! I knew how to start, just wasn't sure the steps to go!

## Answer this Question

## Related Questions

- math - solve the equation log2(x+4)-log4x=2 the 2 and 4 are lower than the g ...
- Math - Logarithmic - Solve: 2^(5x-6) = 7 My work: log^(5x-6) = log7 5x - 6(log2...
- Logarithms - I'm working on logarithmic equations and I'm stuck on how my book ...
- Algebra 2 - solve log2(3x-1)-log2(x-1)=log2(x+1) i have absolutely no idea how ...
- math/algebra - solve the equation log2(3x-2) - log2 (x-5)=4
- college algebra, Please help!! - solve the following logarithmic equation 2log2(...
- Algebra II - Solve log2(7x-3)>= log2(x+12) My work: 6x=15 x=15/6 x-5/2 so my ...
- Pre Cal - Been trying to solve this equation and I keep getting 3...any advice ...
- algebra - Solve for x 1. log5 X=3 2. Log2 16-log2 =x 3. Log9 6561=x
- Math Algebra 2 - How do I put log in a TI-84 calculator. #1.Express the ...