Write the first four terms of the following sequence. Assume that n starts at 1. an= (-(n-4)/6n)
I am not sure how to start this.
=[-(1-4)/6(1)]
=[-(-3)/6]
=(3/6)
=.5
=[-(2-4)/6(2)]
=[-(-2)/12]
=(2/12)
=2
=.17
=[-(3-4)/6(3)]
=[-(-1)/18]
=(1/18)
.05
To find the first four terms of the sequence, you need to substitute values of n from 1 to 4 into the given expression for an.
Let's start by substituting n=1 into the expression:
a1 = (-(1-4)/(6*1))
a1 = (-(3)/6)
a1 = (-3/6)
a1 = -1/2
Now substitute n=2:
a2 = (-(2-4)/(6*2))
a2 = (-(2)/12)
a2 = (-2/12)
a2 = -1/6
Substitute n=3:
a3 = (-(3-4)/(6*3))
a3 = (-(1)/18)
a3 = (-1/18)
Lastly, substitute n=4:
a4 = (-(4-4)/(6*4))
a4 = (-(0)/24)
a4 = 0
Therefore, the first four terms of the sequence are:
a1 = -1/2, a2 = -1/6, a3 = -1/18, a4 = 0
To find the first four terms of the sequence given by an = (-(n-4)/6n), we can substitute values for n starting from 1 and calculate the corresponding terms.
Let's find the value of a1 (the first term) first:
a1 = (-(1-4)/6(1))
= (-(3)/6)
= -3/6
= -1/2
Next, let's find the value of a2 (the second term):
a2 = (-(2-4)/6(2))
= (-(2)/12)
= -2/12
= -1/6
Similarly, let's find the value of a3 (the third term):
a3 = (-(3-4)/6(3))
= (-(1)/18)
= -1/18
Finally, let's find the value of a4 (the fourth term):
a4 = (-(4-4)/6(4))
= (-(0)/24)
= 0
Therefore, the first four terms of the sequence are:
a1 = -1/2
a2 = -1/6
a3 = -1/18
a4 = 0