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April 16, 2014

April 16, 2014

Posted by **NEED HELP NOW!** on Friday, July 29, 2011 at 6:58pm.

1/R=1/R(1)+1/R(2)

At what rate does the effective resistance change when R(2) is 100 ohms? Round off your answer to four decimal places

- calculus -
**Damon**, Friday, July 29, 2011 at 7:09pmR = R1 R2/(R1+R2)

R1 is constant

dR = R1 [(R1+R2) dR2- R2 dR2]/ (R1+R2)^2

dR/dt = R1 dR2/dt [R1]/(R1+R2)^2

dR/dt = 100(2) /(110)^2

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