Posted by **KEViN** on Friday, July 29, 2011 at 11:01am.

A country's population in 1991 was 15 million. In 2001 it was 16 million. Estimate the population in 2005 using exponential growth formula. Round your answer to the nearest million.

- Algebra 2 -
**Reiny**, Friday, July 29, 2011 at 11:34am
let N = 15 e^(kt), where N is in million, t is in years since 1991 and k is a constant

when t = 10 , N = 16

16 = 15e^(10k)

1.0666667 = e^(10k)

ln 1.0666667 = 10k

k = .006456852

then when t = 14

N = 15e^(14(.00645852)) = 16.418

So to the nearest million it would still be 16 million

## Answer This Question

## Related Questions

- algebra - A country's population in 1995 was 175 million. In 2000 it was 181 ...
- algebra - A country's population in 1993 was 171 million estimate the population...
- Algebra - In 2006 population of country was 32.2 million. This represented an ...
- Algebra Help - In 2006 population of country was 32.2 million. This represented ...
- math - In 2006, the population of the country was 32.3 million. This represented...
- Math - In 2006 population of country was 32.2 million. This represented an ...
- math - Date US Population Jul 1, 2012 313.85 million Jul 1, 2011 311.59 million...
- algebra - The population of a particular country was 29 million in 1985; in ...
- Math - Solve. The population of a particular country was 29 million in 1980; in ...
- calculus - The population of a country was 8.4 million people in 2000. Three ...

More Related Questions