Tuesday
March 28, 2017

Post a New Question

Posted by on .

Find the vertex, value of p, axis of symmetry, focus, and directrix for x – 4 = (-1/6)(y + 2)^2

  • Pre-Calc - ,

    x = -1/6(y+2)^2 + 4. x-parabola.
    h = 4, k = -2, a = -1/6, [4a] = 2/3.

    F(X1,-2), V(4,-2), D(X2,-2).

    X1=h - [1/4a] = 4 - 3/2 = 5/2 = 2 1/2.

    X2 = h + [1/4a] = 4 + 3/2 = 5 1/2.

    Axis = k = -2.

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question