Sunday

March 29, 2015

March 29, 2015

Posted by **Cynthia** on Friday, July 29, 2011 at 10:01am.

- calculus -
**MathMate**, Saturday, July 30, 2011 at 7:09pmX=Lim xe^(-x)

x->∞

=Lim x/e^x

x->∞

L'hôpital's rule is applicable if direct evaluation results in an indeterminate form, which is the case here.

To apply the rule, differentiate both numerator and denominator to give

X=Lim 1/e^x

x->∞

=0

**Answer this Question**

**Related Questions**

calculus, limits, l'hopital - Using l'hopital's rule, find the limit as x ...

calculus - This is a question related to L'hopital's rule. lim x -> -infinity...

Calculus - This is a question related to L'hopital's rule. lim x -> -infinity...

calculus, limits, l'hopital - Using l'hopital's rule, find the limit as x ...

Calculus - Using L'Hopital's Rule, find the limit: lim x->0+ (as x approaches...

calculus - Evaluate: (without using Hopital's rule) d) lim (6-3x)/(((5x+6)^1/2)-...

calculus - The limit as x approaches infinity of (e^x+x)^(1/x). I got that it ...

calculus - if i define the function f(x)= x^3-x^2-3x-1 and h(x) = f(x)/g(x), ...

AP Calculus - if i define the function f(x)= x^3-x^2-3x-1 and h(x) = f(x)/g(x), ...

Calculus - Evaluate the following limits. lim as x approaches infinity 6/e^x + 7...