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July 30, 2014

July 30, 2014

Posted by **Cynthia** on Friday, July 29, 2011 at 10:01am.

- calculus -
**MathMate**, Saturday, July 30, 2011 at 7:09pmX=Lim xe^(-x)

x->∞

=Lim x/e^x

x->∞

L'hôpital's rule is applicable if direct evaluation results in an indeterminate form, which is the case here.

To apply the rule, differentiate both numerator and denominator to give

X=Lim 1/e^x

x->∞

=0

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