Posted by Anonymous on Thursday, July 28, 2011 at 3:43pm.
First race car driver:
time = distance / speed
time = 50 miles / 90 mph
time = 0.55556 x 60
time = 33 minutes 20 seconds
The first race car driver will took 33 minutes & 20 seconds to finish the race
Fifteen minutes later a second race car drive start
time = distance / speed
time = 50 miles / 120 mph
time = 0.41667 x 60
time = 25 minutes
The second race car driver will took 25 minutes to complete the 50 miles
Now, add 25 minutes & 15 minutes = 40 minutes
Therfore, the first race car driver will finish 6 minutes & 40 seconds before the second race car driver.
Related Questions
physics - Two cars start from rest at the same location and at the same instant ...
math - Suppose that a certain municipality uses the equation y=3(x-50)+30 to ...
physics - A bicyclist starts a timed race at 6 mph In order to win, he must ...
physics help please! - A race car is one lap behind the lead race car when the ...
physics - A toy race car starts from rest on a circular track of radius 4.30 m. ...
physics - A toy race car starts from rest on a circular track of radius 4.30 m. ...
Math - A race car starts from rest on a circular track of radius 565 m. The car...
math - A race car can travel 3 laps in 10 minuets. How long would it take the ...
physic - In order to qualify for the finals in an race, a runner must achieve an...
math - Jon and Remy were in a car race. When Jon finished the race in 45min, ...
For Further Reading