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December 20, 2014

December 20, 2014

Posted by **Ashley** on Thursday, July 28, 2011 at 12:44am.

Thanks

- math -
**Dr Russ**, Thursday, July 28, 2011 at 3:45amStart by rearranging into

2a^2-7a+3=0

Then either use the formula or it is possible to see the roots by inspection.

(a-3)(a-1/2)=0

- math -
**Ashley**, Thursday, July 28, 2011 at 12:44pm2a^2+3=7a

2a^2-7a+3=0

2a-1)*(a-3)=0

2a-1=0 or a-3=0

a=1/2 or a=3

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