Posted by **Chloe** on Wednesday, July 27, 2011 at 10:17pm.

An object 0.600 cm tall is placed 16.5 cm to the left of the vertex of a concave mirror having a radius of curvature of 22.0 cm. (a) Draw a principle-ray diagram showing the formation of the image. (b) Calculate the position, size, orientation (erect or inverted), and nature (real or virtual) of the image.

- Physics -
**drwls**, Thursday, July 28, 2011 at 4:06am
We can't plot ray diagrams for you.

For the image location, use the standard equation, which you should know.

1/Di + 1/Do = 1/f

f = R/2 = 11 cm is the focal length

Do is the object distance

Di is the image distance

1/Di + 1/16.5 = 1/11

Di = 33 cm

Magnification = Di/Do = 2

It is a real inverted image.

## Answer This Question

## Related Questions

- Physics - A concave mirror has a radius of curvature of 3.4 cm. (a) Determine ...
- Physics - A concave spherical mirror has a radius of curvature 15 cm. A 1 cm ...
- physics - A 4.5 cm tall object is placed 20 cm in front of a spherical mirror. ...
- physics --- - A concave spherical mirror has a radius of curvature 15 cm. A 1 cm...
- physics - A concave spherical mirror has a radius of curvature 15 cm. A 1 cm ...
- science!! - Draw a ray diagram for an object 2 cm tall located 15 cm away from a...
- science - A 3.5-cm tall object is placed 10.0 cm in front of a concave mirror ...
- Physics - A spherical concave mirror has a raduis of curvature of 6.0 cm. At ...
- physics - A concave mirror has a radius of curvature of 0.975 m. An object is ...
- Physics - A convex mirror has a radius of curvature of 36.0 cm. When a 5.60 cm ...

More Related Questions