An object 0.600 cm tall is placed 16.5 cm to the left of the vertex of a concave mirror having a radius of curvature of 22.0 cm. (a) Draw a principle-ray diagram showing the formation of the image. (b) Calculate the position, size, orientation (erect or inverted), and nature (real or virtual) of the image.
Physics - drwls, Thursday, July 28, 2011 at 4:06am
We can't plot ray diagrams for you.
For the image location, use the standard equation, which you should know.
1/Di + 1/Do = 1/f
f = R/2 = 11 cm is the focal length
Do is the object distance
Di is the image distance
1/Di + 1/16.5 = 1/11
Di = 33 cm
Magnification = Di/Do = 2
It is a real inverted image.
Physics - Mark, Wednesday, November 30, 2016 at 12:39pm
F*** you! That wasn't the right answer!