posted by jude on .
describe the force board experiment to show how to obtain the resultant of two non-parallel coplanar force acting at a point.four forces of magnitude 10N, 5N, 4N, AND 6N acts on an oblect in the direction north. West, east and south respectively.find the magnitude and direction of their resultant
X = hor = 4 + (-5) = -1N.
Y = ver = 10 + (-6)
R = sqrt(x^2+y^2) = sqrt(1+16) = 4.12
tanA = Y / X = 4 / -1 = -4,
A = -76 deg, CW = 180-76 = 104 deg =