Posted by **Anonymous** on Wednesday, July 27, 2011 at 1:42pm.

A rectangular poster has an area of 190in(squared). The height of the poster is 1in. less than twice its width. Find the dimensions of the poster.

- math -
**Anonymous**, Wednesday, July 27, 2011 at 3:54pm
A = Area= 190 in^2

H = Hight

W = Width

H = 2W-1

A = W*H

A = W*(2W-1)

190 = 2W*W-1*W

190 = 2W^2-W

2W^2-W-190 = 0

The exact solutions of this equation are:

W=10

and

W= -19/2

Width can't be negative so:

W = 10 in

H = 2*W-1

H = 2*10-1

H = 20-1

H = 19 in

W = 10 in

H = 19 in

A = W*H

A = 10*19

A = 190 in^2

If you don't know solve quadratic equation, in google type:

quadratic equation online

When you see list of results click on:

Free Online Quadratic Equation Solver:Solve By Quadratic Formula

When page be open in rectangle type:

2W^2-W-190=0

and click option: solve it!

You will see solution step-by-step

## Answer This Question

## Related Questions

- Calculus - The top and bottom margins of a poster are 2 cm and the side ...
- calulus - The top and bottom margins of a poster are 8 cm and the side margins ...
- math please help - Marissa is designing a rectangular poster whose width is 2/3...
- math - a poster is 25cm taller than it is wide. it is mounted on a piece of ...
- college algebra - Marissa is designing a rectangular poster whose width is 2/3 ...
- math - A rectangular poster is to have 50 squared inches for printed matter. It...
- calculus - The top and bottom margins of a rectangular poster are 6 centimeters ...
- Math - The top and bottom margins of a poster are 6 cm and the side margins are...
- Math - The top and bottom margins of a poster are 8 cm and the side margins are...
- Math calculus - The top and bottom margins of a poster are 8 cm and the side ...

More Related Questions