Posted by **Anonymous** on Wednesday, July 27, 2011 at 1:42pm.

A rectangular poster has an area of 190in(squared). The height of the poster is 1in. less than twice its width. Find the dimensions of the poster.

- math -
**Anonymous**, Wednesday, July 27, 2011 at 3:54pm
A = Area= 190 in^2

H = Hight

W = Width

H = 2W-1

A = W*H

A = W*(2W-1)

190 = 2W*W-1*W

190 = 2W^2-W

2W^2-W-190 = 0

The exact solutions of this equation are:

W=10

and

W= -19/2

Width can't be negative so:

W = 10 in

H = 2*W-1

H = 2*10-1

H = 20-1

H = 19 in

W = 10 in

H = 19 in

A = W*H

A = 10*19

A = 190 in^2

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2W^2-W-190=0

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