Posted by Anonymous on Wednesday, July 27, 2011 at 1:42pm.
A rectangular poster has an area of 190in(squared). The height of the poster is 1in. less than twice its width. Find the dimensions of the poster.

math  Anonymous, Wednesday, July 27, 2011 at 3:54pm
A = Area= 190 in^2
H = Hight
W = Width
H = 2W1
A = W*H
A = W*(2W1)
190 = 2W*W1*W
190 = 2W^2W
2W^2W190 = 0
The exact solutions of this equation are:
W=10
and
W= 19/2
Width can't be negative so:
W = 10 in
H = 2*W1
H = 2*101
H = 201
H = 19 in
W = 10 in
H = 19 in
A = W*H
A = 10*19
A = 190 in^2
If you don't know solve quadratic equation, in google type:
quadratic equation online
When you see list of results click on:
Free Online Quadratic Equation Solver:Solve By Quadratic Formula
When page be open in rectangle type:
2W^2W190=0
and click option: solve it!
You will see solution stepbystep
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