Posted by Robert on .
The formula h=48t16t^2 gives the height, h, in feet, of an object projected into the air after t seconds. If an object is propelled upward, at what time(s) will it reach a height of 32 feet above the ground?

Math 
Henry,
h = 48t  16t^2 = 32 Ft.
Divide both sides by 16:
3t  t^2 = 2,
t^2 + 3t  2 = 0.
Solve using the Quadratic Eq and get:
t = 1s, and t = 2s.