Homework Help: Math-confused!

Posted by Jen on Wednesday, July 27, 2011 at 9:49am.

A disc jockey has 12 songs to play. Seven are slow songs, and five are fast songs. Each song is to be played only once. In how many ways can the disc jockey play the 12 songs if:

*The songs can be played in any order.
*The first song must be a slow song and the last song must be a slow song.
*The first two songs must be fast songs.

Assistance needed -- "how many different ways" - Writeacher, Wednesday, July 27, 2011 at 9:52am
http://www.jiskha.com/display.cgi?id=1311727672
Math-confused! - Reiny, Wednesday, July 27, 2011 at 9:57am
a) played in any order = 12!
b) 1st and last slow, = 7(10!)(6)
.... 7 in the first spot, 6 in the last spot, leaving 10 for the rest
c) 1st two must be fast = 5(4)(10!)
Math-confused! - Jen, Wednesday, July 27, 2011 at 12:18pm
gosh thats so confusing :(

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