Posted by Jen on Wednesday, July 27, 2011 at 9:48am.
????
Did you mean C(5,3) or 5C53 ?
If so, then
C(5,3) = 5!/(3!2!) = 120/(6(2)) = 120/12 = 10
in general
C(n,r) , read "n choose r"
= n!/( ( n-r)!r! )
It should be:
like the second one you put but 5 ^C3(not the extra 5 after the C)....its very confusing to me :(
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