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April 18, 2014

April 18, 2014

Posted by **Jen** on Wednesday, July 27, 2011 at 9:48am.

- Math -
**Reiny**, Wednesday, July 27, 2011 at 10:02am????

Did you mean C(5,3) or_{5}C_{53}?

If so, then

C(5,3) = 5!/(3!2!) = 120/(6(2)) = 120/12 = 10

in general

C(n,r) , read "n choose r"

= n!/( ( n-r)!r! )

- Math -
**Jen**, Wednesday, July 27, 2011 at 12:17pmIt should be:

like the second one you put but 5 ^C3(not the extra 5 after the C)....its very confusing to me :(

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