Posted by noah on Tuesday, July 26, 2011 at 11:22pm.
The spring constant is
k = Mg/0.215m = 57.0 N/m
The frequency of oscillation is
f = [1/(2 pi)]sqrt(k/m) = 1.075 Hz
The angular frequency is
w = sqrt(k/m) = 6.75 rad/s
The period is 1/f = 0.93 seconds
(a) 1/4 period = 0.2325 s is the time needed to return to the equilibrium position
(b) If y is measured from the equilibrium position
y = 0.13 cos wt = 0.14 cos6.75t
(c) Max speed = w*(amplitude)= 0.13 w
Max acceleration = w^2*(amplitude)
Related Questions
college physic - A 1.25kg mass stretches a vertical spring 0.215m.If the spring ...
Physics - A mass of 1.66 kg stretches a vertical spring 0.312 m. If the spring ...
Physics - .A mass of 1.61 kg stretches a vertical spring 0.313 m. If the spring ...
Math - The distance a spring stretches is directly proportional to the force ...
physic - Two equal masses are attached to separate identical springs next to one...
physics - One end of a massless coil spring is suspended from a rigid ceiling. ...
physics - One end of a massless coil spring is suspended from a rigid ceiling. ...
College Algebra - Hooke's Law states that the distance a spring stretches is...
physics - a 500-g mass is attached to the end of an initially unstretched ...
Physics - A weight stretches one spring 3 in. and a second weight stretches ...
For Further Reading
