Homework Help: Calculus :)

Posted by Brit on Tuesday, July 26, 2011 at 8:37pm.

A rectangle is inscribed with its base on the x-axis and its upper corners on the parabola y=6–x^2. What are the dimensions of such a rectangle with the greatest possible area?

Find Width=____ & Height=4

just need to find width.. is not 2

Calculus :) - Reiny, Tuesday, July 26, 2011 at 8:50pm
let the point of contact be (x,y)
then the base is 2x and the height is y

area = 2xy = 2x(6-x^2) = 12x - 2x^3
d(area)/dx = 12 - 6x^2
= 0 for a max of area
6x^2 = 12
x^2 = 2
x = √2, then y = 6-2 = 4

rectangle has a base of 2√2 and a height of 4

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