math
posted by jessica on .
find a quadratic function whose graph has a max of 25 and xintercepts of 3 and 2.

(3,0), (2,0).
y = a(xh)^2 + k.
h = (3+2) / 2 = 1/2.
y = a(2(1/2))^2 + 25,
25a/4 + 25 = 0,
25a + 100 = 0,
25a = 100,
a = 4.
y = 4(x+1/2)^2 + 25 = Vertex form.
y = 4(x^2 + x + 1/4) + 25,
y = 4x^2  4x  1 +25,
y = 4x^2  4x + 24,