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April 18, 2015

April 18, 2015

Posted by **Lynda** on Tuesday, July 26, 2011 at 12:42pm.

/b2-4ac; b=3, a=-1, c=-2

What would the solution be?

- algebra -
**Anonymous**, Tuesday, July 26, 2011 at 12:54pmb^2-4ac=9-8=1

X1=(-b-sqrt(1))/2a=(-3-1)/(-2)=2

X2=(-b+sqrt(1))/2a=(-3+1)/(-2)=1

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