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October 31, 2014

October 31, 2014

Posted by **Anna** on Tuesday, July 26, 2011 at 1:04am.

Find the value of x and find the new dimensions of the frame.

How do you do this?? Please show work

- Alg 2 -
**Anonymous**, Tuesday, July 26, 2011 at 2:12amL = Lenght = 8 in

W = Width = 4 in

A = Area = L*W = 8*4 = 32 in^2

3A = 3*32 = 96 in^2

(L+x)*(W+x) = 3A

(8+x)*(4+x) = 96

4*8 + 4*x + x*8 + x*x = 96

32 + 4x + 8x + x^2 = 96

x^2 + 12x + 32 - 96 = 0

x^2 + 12x - 64 = 0

The exact solutions of this equation are:

x = 4

and

x = -16

Distance can't be negative so:

x=4

(8+4) * (4+4) = 12 * 8 = 96 in^2 = 3A

- Alg 2 -
**Anonymous**, Tuesday, July 26, 2011 at 2:15amThe new dimensions of the frame are:

Lenght = 8+4 = 12 in

Width = 4+4 = 8 in

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