a car pulling a 1500-kg trailer produces an acceleration of 0.50m/s^2.
a)the frictional force in the wheels of the trailer is 125N. what force is the car exerting on the trailer?
b) what force is the trailer exerting on the car?
a) Fnet (on trailer) = M*a
= 1500*0.5 = 750 N
= Fcar - Fwheels
= Fcar - 125
Fcar = 875 N
b) -875 N (oppostite reaction)
To find the force that the car exerts on the trailer, we can use Newton's second law of motion, which states that the force exerted on an object is equal to the mass of the object multiplied by its acceleration.
a) Force exerted by the car on the trailer:
Given:
Mass of the trailer (m) = 1500 kg
Acceleration (a) = 0.50 m/s²
Using Newton's second law, we can calculate the force (F) exerted by the car on the trailer:
F = m * a
F = 1500 kg * 0.50 m/s²
F = 750 N
Therefore, the force exerted by the car on the trailer is 750 Newtons.
To find the force that the trailer exerts on the car, we need to consider the principle of action and reaction, also known as Newton's third law of motion. According to this law, the force exerted by the trailer on the car is equal in magnitude and opposite in direction to the force exerted by the car on the trailer.
b) Force exerted by the trailer on the car:
Given:
Frictional force in the wheels of the trailer (Ff) = 125 N
Since the frictional force acts in the opposite direction to the motion, we need to subtract it from the force exerted by the car on the trailer to get the force exerted by the trailer on the car. Therefore:
Force exerted by the trailer on the car = Force exerted by the car on the trailer - Frictional force
Force exerted by the trailer on the car = 750 N - 125 N
Force exerted by the trailer on the car = 625 N
Therefore, the force exerted by the trailer on the car is 625 Newtons.
1500*0.5=750
750+125=875