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December 19, 2014

December 19, 2014

Posted by **Ashley** on Monday, July 25, 2011 at 9:25pm.

describe the end behavior of f, please describe in detail how you got the answer and explain your abbreviations.

- Pre cal -
**Henry**, Tuesday, July 26, 2011 at 10:33pmF(x) = 3*2^x.

F(-2) = 3 * 2^-2 = 0.75.

F(-1) = 3 * 2^-1 = 1.50.

F(0) = 3 * 2^0 = 3.0.

F(1) = 3 * 2^1 = 6.0

So when x is increased by 1, F(x) doubles. This is normal behavior for

base 2 numerals.

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