Posted by **Ash** on Monday, July 25, 2011 at 7:09pm.

solve x^2e^x+9x^ex=0

- college algebra -
**Henry**, Tuesday, July 26, 2011 at 10:10pm
x^2e^x + 9xe^x = 0.

Factor out e^x:

e^x(x^2+9x) = 0,

Divide both sids by e^x:

x^2 + 9x = 0,

x(x+9) = 0,

x = 0.

x + 9 = 0,

x = -9.

Solution Set: x = 0, and x =-9.

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