Posted by amy on Monday, July 25, 2011 at 7:05pm.
Vi = -64 m/s (velocity is down)
dv/dt = a = +7m/s^2 (acceleration is up)
h = hi + Vi t + (1/2) a t^2
h - hi = -64(10) + 3.5 (100)
= -640 + 350
= - 290
so it went down 290 meters
would there be any formulas you would have to use to get this answer for grade 11 math
h = hi + Vi t + (1/2) a t^2
usually
x = Xi + Vi t + (1/2) a t^2
In first one second it descends 64 m ,
Next one second it descends =(64-7)=57 m
Then next one second it descends = ( 57-7)=50 m,
4th second it descends =50-7=43 m
5th second it descends = 43-7=36 m.
6th second it descends = 36-7=29 m.
7th second it descends = 29- 7= 22 m
8th second it descends = 22-7=15 m
9th second it descends = 15-7=8 m.
10th second it descends = 8-7=1 m
Total distance covered by it= 64+57+50+43+36+29+22+15+8+1= 325 m
Related Questions
PHYSICSS!!! - still cant get this one? so damon i know you wanna help! or ...
Physics - A spaceship lifts off from the Earth with constant acceleration. 9 ...
physics - An 85.4 kg astronaut is working on the engines of a spaceship that is ...
Physics - An 95.0 kg astronaut is working on the engines of a spaceship that is ...
Science - An alien spaceship is revolving around a spherical asteroid in a very...
Physics - A 83.5 kg astronaut is working on the engines of a spaceship that is ...
physics - A 87.2 kg astronaut is working on the engines of a spaceship that is ...
physics - A 87.2 kg astronaut is working on the engines of a spaceship that is ...
physics - A spaceship is observed traveling in the positive x direction with a ...
Trig - A ship leaves its homeport and sails on a bearing of N28degrees10'E. ...
For Further Reading