Posted by **Natalie** on Monday, July 25, 2011 at 3:55pm.

Use the “difference of squares” rule to factor the following expression

49-4y^2

my answer is going to be (7-2y)(7-2y)

I wasn't sure if it could of been (7-2y)(7+2y)

- math -
**Sam**, Monday, July 25, 2011 at 4:20pm
Your answer should be (7-2y)(7+2y).

If you multiply the first equation (7-2y)(7-2y) it would equal 49-14y-14y+4y^2. After simplifying it would equal 49-28y+4y^2. The second option multiplies out to 49+14y-14y-4y^2. The 14y's cancel each other. That leaves 49-4y^2. Hope that helps.

- math -
**Natalie**, Monday, July 25, 2011 at 11:30pm
Thank You So Much Sam! :)

## Answer This Question

## Related Questions

- math - Use the “difference of squares” rule to factor the following expression ...
- algebra - use the "difference of squares" rule to factor the following ...
- algebra - use the "difference of squares" rule to factor the following ...
- algebra - Use the “difference of squares” rule to factor the following ...
- intermediate algebra - Use the difference of squares rule to factor the ...
- Math - Use common factoring and the difference of two squares to factor each ...
- ALGEBRA - Can someone explain the following to me? 1.How do you factor the ...
- math help - can someone explain to me how i should factor this problem? x^6-64 ...
- Algebra - I have a few more questions that I either need help with or just need ...
- Math (factoring) - Can someone check my answer? 5x^3 - 40 =5(x^3-8) =5(x-2)(x^2+...

More Related Questions