Posted by **Natalie** on Monday, July 25, 2011 at 1:50pm.

Andrew factored the expression 28x^3-42x^2+35x as 7x(4x^2+6x-5). But when Melissa applied the distributive law and multiplied out 7x(4x^2+6x-5) , she got 28x^3+42x^2-35x ; thus, Andrew’s solution does not appear to check. Why is that? Please help Andrew to understand this better. Explain your reasoning and correctly factor the original expression, if possible.

Can someone please help me with this question.

## Answer This Question

## Related Questions

- Math - Andrew factored the expression 28x^3-42x^2+35x as 7x(4x^2+6x-5). But when...
- Intermidia Algebra - Andrew factored the expression -12x^3-28x^2-3x as -4x (3x^2...
- algebra - Andrew factored the expression 28x©ø-6x©÷-10x as 2x(14x©ø-3x©÷-5x) . ...
- algebra - Andrew factored the expression 20x^3-12x^2+8x as 4x(5x^2-12x^2+8x). ...
- Algebra - Andrew factored the expression 20x^3-12x^2+8x as 4x (5x^2-12x^2+8x). ...
- algebra - Andrew factored the expression 54x^3-30x^2+15x as 5x(9x^2-6x+3) but ...
- math - Andrew factored the expression 54x^3-30x^2+15x as 5x(9x^2-6x+3) but when ...
- Algebra - Can someone help me with this please. Andrew factored the expression ...
- Algebra - Megan factored the expression 72x^2-43x+6 as (9x-3)(8x-2). But when ...
- algebra - Megan factored the expression 72x^2-43x+6 as (9x-3)(8x-2). But when ...

More Related Questions