Posted by Jay on Monday, July 25, 2011 at 6:25am.
I'll be glad to check your answer.
Let the 1st # = x
And the 2nd # = y
Difference between the two # is = 72
x - y = 72 ---- Equation 1
Then, one of the # divided by the other # which = 4
x/y = 4 ----Equation 1
x - y = 72 -- eq 1
x / y = 4 -- eq 2
x = 72 + y -- eq 3
Sub eq 3 in eq 2 we get,
[(72 + y) / y] = 4
72 + y = 4y
72 = 4y - y
72 = 3y
y = 72 / 3
y = 24
Now sub y = 24 in equation 1 or equatin 3 and solve for x?
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