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March 4, 2015

March 4, 2015

Posted by **Jay** on Monday, July 25, 2011 at 6:25am.

Option:

a) 22&94

b) 24&96

c) 20&92

d) 30&102

- Math -
**Ms. Sue**, Monday, July 25, 2011 at 11:24amI'll be glad to check your answer.

- Math -
**Mithra**, Monday, July 25, 2011 at 11:32amLet the 1st # = x

And the 2nd # = y

Difference between the two # is = 72

x - y = 72 ---- Equation 1

Then, one of the # divided by the other # which = 4

x/y = 4 ----Equation 1

x - y = 72 -- eq 1

x / y = 4 -- eq 2

x = 72 + y -- eq 3

Sub eq 3 in eq 2 we get,

[(72 + y) / y] = 4

72 + y = 4y

72 = 4y - y

72 = 3y

y = 72 / 3

y = 24

Now sub y = 24 in equation 1 or equatin 3 and solve for x?

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