Posted by **denise ** on Sunday, July 24, 2011 at 11:28pm.

Find all solutions in the unterval [0,2pi), cos x/2-sinx=0

- pre cal 2 -
**Reiny**, Sunday, July 24, 2011 at 11:45pm
from sin2A = 2sinAcosA we can say that

sinx = 2sin(x/2)cos(x/2)

cos(x/2) = 2sin(x/2)cos(x/2)

1= 2sin(x/2)

sin(x/2) = 1/2

x/2 = 30°, 150° or π/6, 5π/6 radians

x = 60°, 300° or π/3, 5π/3 radians

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