Posted by Bud on Sunday, July 24, 2011 at 10:57pm.
g(x) = xe^x
g'(x) = xe^x + e^x
g''(x) = xe^x + e^x + e^x
= e^x( x+2)
at point of inflection g''(x) = 0
so e^x = 0 ----> no solution
or x+2 = 0
x = -2
then g(-2) = -2e^-2 or -2/e^2
point of inflection (-2, -2/e^2)
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