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August 1, 2014

August 1, 2014

Posted by **Bud** on Sunday, July 24, 2011 at 10:57pm.

- Calculus -
**Reiny**, Sunday, July 24, 2011 at 11:04pmg(x) = xe^x

g'(x) = xe^x + e^x

g''(x) = xe^x + e^x + e^x

= e^x( x+2)

at point of inflection g''(x) = 0

so e^x = 0 ----> no solution

or x+2 = 0

x = -2

then g(-2) = -2e^-2 or -2/e^2

point of inflection (-2, -2/e^2)

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