The volume of air in a persons lungs is 615 mL at a pressure of 760 mmHG inhalation occures at the pressure in the lungs drops to 752 mmHG, to wha volume did the lungs expand
I got 615*760=V2*752=621 i keep getting 621 and the answer is 620 what i'am i doing wrong
3 sig figs
To find the volume to which the lungs expanded, you can use Boyle's Law, which states that the initial pressure multiplied by the initial volume equals the final pressure multiplied by the final volume.
Let's denote the initial volume as V1 (615 mL), the initial pressure as P1 (760 mmHg), the final pressure as P2 (752 mmHg), and the final volume as V2.
According to Boyle's Law, we have:
P1 * V1 = P2 * V2
Plugging in the known values, we have:
760 mmHg * 615 mL = 752 mmHg * V2
Now, let's solve for V2:
V2 = (760 mmHg * 615 mL) / 752 mmHg
V2 = 622,381.91 mmHg·mL / 752 mmHg
V2 ≈ 827.17 mL
Therefore, the volume to which the lungs expanded is approximately 827.17 mL, not 620 mL. It seems like there was an error in your calculations.
To solve this problem, we can use the equation relating the initial and final volumes and pressures of a gas:
(P1 × V1) = (P2 × V2)
Let's substitute the values given in the problem:
P1 = 760 mmHg
V1 = 615 mL
P2 = 752 mmHg
V2 = ?
Now, let's rearrange the equation to solve for V2:
V2 = (P1 × V1) / P2
Substituting the values:
V2 = (760 mmHg × 615 mL) / 752 mmHg
Calculating this expression:
V2 ≈ 622.227 mL
Therefore, the volume to which the lungs expanded is approximately 622.227 mL.
It seems like you made a calculation error in your steps. When calculating (615 * 760) / 752, you should get approximately 622.382 mL, not 621. Round the answer to the nearest whole number, and it becomes 622 mL, which explains the discrepancy between your answer and the correct answer of 620 mL.