Posted by Mona on .
The perimeter of a rectangle is 46m. If the width were doubled and the length were increased by 12m, the perimeter would be 82m. What are the length and width of the rectangle?

Math 
Reiny,
original:
2L+ 2W = 46
L+W = 23
new one:
2(L+12) + 2(2W) = 82
2L + 24 + 4W = 82
L + 2W = 29
Subtract the 1st from the 2nd
W = 6
back in the 1st > L=17
original rectangle is 17 by 6
check: perimeter of original = 34 + 12 = 46
new rectangle is 29 by 12
perimeter of new = 2(29) + 2(12) = 82