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March 25, 2017

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The perimeter of a rectangle is 46m. If the width were doubled and the length were increased by 12m, the perimeter would be 82m. What are the length and width of the rectangle?

  • Math - ,

    original:
    2L+ 2W = 46
    L+W = 23

    new one:
    2(L+12) + 2(2W) = 82
    2L + 24 + 4W = 82
    L + 2W = 29

    Subtract the 1st from the 2nd
    W = 6
    back in the 1st ---> L=17

    original rectangle is 17 by 6

    check: perimeter of original = 34 + 12 = 46
    new rectangle is 29 by 12
    perimeter of new = 2(29) + 2(12) = 82

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