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find the exact solutions in the interval [0,2pi), sin4x=-2sin2x

  • pre cal 2 - ,

    sin4x=-2sin2x
    2 sin2xcos2x = -2sin2x, ......... since sin2A = 2sinAcosA
    cos2x = -1
    2x = 180°, 360°, 540°, 720° which is π , 2π 3π, or 4π radians
    x = 90° ,180°,270°, 360° which is π/2, π , 3π/2, or 2π radians

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