Posted by kc on Sunday, July 24, 2011 at 8:47pm.
sin4x=-2sin2x
2 sin2xcos2x = -2sin2x, ......... since sin2A = 2sinAcosA
cos2x = -1
2x = 180°, 360°, 540°, 720° which is π , 2π 3π, or 4π radians
x = 90° ,180°,270°, 360° which is π/2, π , 3π/2, or 2π radians
Related Questions
Pre-Cal - Approximate the equation's soultions in the interval (o, 2pi). If ...
Pre-Cal(Please help) - Approximate the equation's soultions in the interval...
pre cal - Find all solutions in the interval[0,2pi),cos x/2-sinx=0
Pre CAL!! Please HELP - find the solutions of the equation that are in the ...
Pre CAL!! Please HELP - find the solutions of the equation that are in the ...
Trig - Find all the solutions in the interval [0,2pi). 2sin2x - sqrt(2) = 0 ...
Calculus - I need to find the exact solution to: 2sin2x = sqrt(x)on the interval...
trig - Find the exact solutions of the equation in the interval [0,2pi). sin(x/2...
pre cal 2 - Find all solutions in the unterval [0,2pi), cos x/2-sinx=0
interval - Find the exact solutions on the interval [0,pi]. 2sin2x = sqrt(x) ...
For Further Reading
