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December 20, 2014

December 20, 2014

Posted by **Ashley** on Sunday, July 24, 2011 at 7:29pm.

- Pre Cal -
**Reiny**, Sunday, July 24, 2011 at 9:05pm[x(5x+1)-3(x^2+1)]/ [(x-1)^2]

= (5x^2 + x - 3x^2 - 3)/(x - 1)^2

= (2x^2 + x - 3)/(x-1)^2

= (2x-3)(x+1)/(x-1)^2

mmmh, looks like Much Ado About Nothing.

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