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March 4, 2015

March 4, 2015

Posted by **Angela** on Sunday, July 24, 2011 at 5:44pm.

- Pre cal -
**Damon**, Sunday, July 24, 2011 at 5:54pmmax at t = 0 is a cos function

y = A cos (k theta)

max is 2 so

y = 2 cos (k theta)

min of cos is at (k *pi/4) = pi radians

so k = 4

y = 2 cos (4 theta)

- Pre cal -
**Damon**, Sunday, July 24, 2011 at 6:04pmOh if they insist on sin rather than cos, use phase shift of pi/2

y = 2 sin (4 theta - pi/2)

- Pre cal -
**Anonymous**, Sunday, July 24, 2011 at 7:33pmnot -pi/2 but +pi/2

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