Posted by Kirk on Sunday, July 24, 2011 at 4:11pm.
b = k p + c where k and c are constants
200 = k (3) + c
120 = k (4) + c
------------------subtract
80 = -1 k
so
k = -80
back to first eqn
200 = -80(3) + c
200 = -240 + c
c = 440
so
b = -80 p + 440
Thank you, I was stuck on this for several hours to how to write this out, thank you again!
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