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December 20, 2014

December 20, 2014

Posted by **Kirk** on Sunday, July 24, 2011 at 4:11pm.

- MAT101 -
**Damon**, Sunday, July 24, 2011 at 4:52pmb = k p + c where k and c are constants

200 = k (3) + c

120 = k (4) + c

------------------subtract

80 = -1 k

so

k = -80

back to first eqn

200 = -80(3) + c

200 = -240 + c

c = 440

so

b = -80 p + 440

- MAT101 -
**Kirk**, Sunday, July 24, 2011 at 5:22pmThank you, I was stuck on this for several hours to how to write this out, thank you again!

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